Teams. select distinct; p. snowflake. snowflake. snowpark. approx_percentile_combine. SELECT datediff (MINUTE,cast ( [EndTime] as datetime),cast ( [StartTime] as datetime)) FROM YourTable WHERE TRY_CONVERT (DATETIME, [EndTime]) IS NOT NULL AND TRY_CONVERT (DATETIME, [StartTime]) IS NOT NULL. DATEDIFF() is a function found in SQL Server and MySQL that calculates and returns the difference between two date values. I was changing : CONVERT(DATE, to date_trunc('DAY', GETUTCDATE(), to SYSDATE(),. The * tells Snowflake to look at all columns, but you could have put just one column as it means the same thing. later_date, p. Databricks, on the other hand, has a market share of 8. (Snowflake) is much more elegant, and I meant to mention that option in my answer, but be aware that it does not support time periods of 24 hours or greater. functions. So I got help to get started on this and it runs well. Notas de uso¶. functions. So try converting one of them to other timezone using "CONVERT_TIMEZONE" and thn apply the DATEDIFF function. 2022-02-07 12:57:45. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. So if you run that code in April (today) it's get 30th April. T. ,DATEDIFF(SECOND, DATETIME_1, DATETIME_2) AS DIFF_SECONDS ,DIFF_SECONDS % (60) AS NUM_SECONDS. I am not able to find the right solution for this. Usage Notes¶. DATETIME is an alias for TIMESTAMP_NTZ. Like Liked Unlike Reply. approx_count_distinct. 2022-02-07 12:57:45. date_from, evnt. For example, if we want to get the name ‘John’ from the name ‘John Rose’, then we can make use of this function as: substring (‘John Rose’,0,4). If only a time value is assigned to a date data type variable, DATEDIFF sets the value of the missing date part to the default value: 1900-01-01. datediff(part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Here are some great date functions to round out your toolkit. : pip install data-diff 'data-diff [postgresql,snowflake]' -U. 함수 요약If one of the arguments is a number, the function coerces non-numeric string arguments (e. for the first record, it must be calculated from 9am on 2021-05-19, hence the result would be 45 minutes. Stack Overflow. If the value of Nweek = '201834' then the value of IDate is returned as '2018-08-20' If the value of Nweek =. Alias for DATEDIFF. The timestamp data type always contains milliseconds. Let’s look at the clear differences between the two. Alias for DATEADD. sql 명령 참조. *, (date2 > date1 + interval '28 day') as flag from t; Share. snowpark. functions. For ' integer ' (a string containing an integer), the integer is treated as a number of seconds, milliseconds, microseconds, or. datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. ,DATEDIFF(SECOND, DATETIME_1, DATETIME_2) AS DIFF_SECONDS. Snowflake. ms from a date to the midnight? How to calculate the time difference in format hh:mm:ss. I have this piece of code that works in SQL server. Invalid function type [TIMEDIFF] for window function. Extracts the specified date or time part from a date, time, or timestamp. CREATE OR REPLACE FUNCTION fn_get_timestamps_in_range (grain VARCHAR, start_tsmp TIMESTAMP_TZ, end_tsmp TIMESTAMP_TZ) RETURNS. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. Run data-diff with connection URIs. Sorted by: 2. String concatenation will build '1' + ',' + '27'. Accepts relevant date and time parts (see next section for details). See. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. はじめに Snowflake の 日時(日付、時刻含む)について 少しづつだが、まとめておく。 目次 【1】日時(日付、時刻含む)のデータ型 【2】現在日時を返す関数 【3】日時(日付、時刻含む)の変換 1)キャスト 2)DATE_FROM_PARTS関数 【4】日時の計算 1)DATEADD関数 2)DATEDI… Snowflake does not allow to run session variable statement and dashboard query statement together. functions. Databricks vs Snowflake: Performance. The DATEDIFF() function returns an integer that represents the number of days between two dates. SELECT AVG (CAST (DATEDIFF (d, DateUsed, DateExpires) AS FLOAT)) FORM tbl. functions. snowflake. A window function is any function that operates over a window of rows. From MySQL docs: DATEDIFF() returns expr1 − expr2 expressed as a value in days from one date to the other. functions. June 3-6, 2024. The value must be the same data type as the expr, or must be a data. A possible workaround, especially if your data is not very large, is to create a new table with the exact schema you want and move the. 0 );This is the date or timestamp expression to which you want to add a specified number of months. たとえば、 DATEDIFF (milliseconds, '00:00:00', '00:00:01. highest, second-highest, etc. There are certain use case scenarios when it is recommended to use the DATEDIFF function within the Snowflake cloud data warehouse which are as follows: If we want to find the difference between two dates in the form of days, years, or months. date1 and date2 are the respective starting and ending dates for which you are about to find the difference. functions. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. 2. functions. snowpark. DATEDIFF on several events for specific value. For example, if you want to add 2 days to August 1, 2018, then this will be '2018-08-01'::DATE. Setting a clustering key is important on large fact tables. g. We would like to show you a description here but the site won’t allow us. Note that unit values can be different in SQL Server DATEDIFF and MariaDB TIMESTAMPDIFF. When using datediff to calculate a year, it only looks at the year. (Most window functions require at least one column or. For source_tz and target_tz, you can specify a time zone name or a. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. e. 124 seconds. snowflake. I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. array_aggSnowflake is imho for doing complex queries that don't run elsewhere, so why would you run them the worst way, just to "hide" some complexity that is not that complex. The string must start with the first two characters (case-insensitive) of the day name: su (Sunday) mo (Monday) tu (Tuesday) we (Wednesday) th (Thursday)Join our community of data professionals to learn, connect, share and innovate together. functions. Arguments. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. The value can be a literal or an expression. It can be one of the following formats: Year:. Excluding only weekends doesn't work for business purposes. p. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. A window function is any function that operates over a window of rows. orders AS ord1 LEFT. Usage Notes¶. INFORMATION_SCHEMA. . I want to calculate now the time difference in days between 1 and 2 (if not '0000-00-00') or 3 (if 2. In Snowflake, you will need to run the TIMEDIFF /TIMESTAMPDIFF command with date part of "SECOND" so you do not lose any precision. From Snowflake. You can use these interval literals in conditions and calculations that involve date-time expressions. approx_percentile_accumulate1) I don't know what the % indicates in SQL Server, but in Snowflake it is DATEADD(millisecond, <# to add>, <value to be added to>) 2) the TO_VARCHAR function doesn't take SQL Server format numbers. What about bank holidays? The typical way this is handled is to create a Calendar table with one row per day for the next N years, with fields for year, month, week number, day etc and flags that determine whether it's a working day, holiday, weekend etc. 1. One of the examples in the Examples section below illustrates the. mysql - Disable ONLY_FULL_GROUP_BY - Stack Overflow. (Most window functions require at least one column or. date_from, evnt. Fractional seconds are not rounded. 複数の行が評価される場合(例: 入力が複数の行を含むテーブルの列名である場合)、値が秒. Return a percentile value based on a continuous distribution of the input column (specified in order_by_expr). To Here is an example of changing a TIMEZONE at the session level: ALTER SESSION SET. 1. snowpark. Hi @SQL Baby , Last Day of previous month:. Know everything you need about Snowflake DATEDIFF. If you need the difference in seconds (i. You can use the SWITCH statement form of CASE thus you just need to branch the options you want, and matching one will be used. datediff¶. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in depth if required Add links and other resources as. 1 There are several ways to approach this, but here's the way I do it with SQL Generator function Datespine_Groups. start <= w. 3. Le signe moins ( -) peut également être utilisé pour soustraire des dates. snowpark. To change the rounding mode to round the value half to even (e. 123秒を返します。. DATEDIFF. what I need is to expand their dates for each record, for example: id | date_start | date_end 1 | 2019-12-01 | 2019-12-05 2 | 2020-01-01 |. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. 0 to 59. g. I want the end result to be a date. Want to elevate your date analytics in Snowflake? In the Snowflake documentation it mentions that the result of an SQL expression can be set to the value of a variable so I tried the following and it seems to work okay: SET MONTH_DELTA = ( select DATEDIFF ( month , '1900-01-01' , '1901-01-01' )); -- Works !! Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO_DATE、 TO_TIME または TO_TIMESTAMP を呼び出すことをお勧めします。. Window functions that calculate rank (e. The. In almost all cases, at least one of those expressions references a column in that row. My time stamps are down to the milisecond. If end_date or start_date is NULL, the DATEDIFF() function returns NULL. A common business problem is calculating the number of working days or hours between two timestamps. of days as: days start_date end_date 14 2022. However then. The data type of the variable is derived from the data type of the result of the evaluated expression. If you want the "exact" (as far as floating point gets) average, use. Simple right? The only thing is that difference in years is duplicated here. The documentation can be found here:. functions. In terms of Ingestion performance, Databricks provides strong Continuous and Batch Ingestion with Versioning. MSSQL_CONVERT. Use the datediff() function to calculate the shipping time, meaning how long the customer must. Alias for DATEDIFF. functions. I initially had an issue with loading long timestamps (9999-12-31 23:59:59. 3 and above. User Conference. I'm am fairly new to using these systems and I am trying to convert the below statement for Snowflake, but no matter what i change, I keep getting errors. Want to elevate your date analytics in Snowflake?It looks like the function DATEADD / DATEDIFF is causing it to fail: SET MONTH_DELTA = ABS (-1);--works; SET MONTH_DELTA = CURRENT_DATE;--works; SET MONTH_DELTA = DATEDIFF (month, '1900-01-01', '1901-01-01');--doesn 't work; In the Snowflake documentation it mentions that the result of an SQL expression can be set to the value of. MSSQL on the other hand does an implicit cast of '0' to DATE '1900-01-01' and returns the result in the requested date part. functions. It may be positive or negative. Expression to be converted into a time: For string_expr, the result of converting the string to a time. date_expr. 124秒ではなく、1. datediff (part: str, col1: Union [Column, str], col2: Union [Column, str]) → Column [source] ¶ Calculates the difference between two date, time, or. The function returns the result of. Snowflake. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号(-)を使用して日付を減算することもできます。Why DATEDIFF() function in Snowflake works differently while getting date difference in weeks. 5 is rounded to -1. insertedon,1,10))) There is any simple way to do this? just a subtraction of 2 hours to date time Regards. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go. (datediff(DAY, uc. The function returns the result of subtracting. So far I have this: SELECT evnt. Example:1 Answer. Is there any inbuilt function that provides the timestamp instead of computing the datediff every time? In both cases above the output timestamp is epoch timestamp corresponding to the CURRENT_DATE (which is the current time in the snowflake account time zone). set @BegDate = DATEADD(month, DATEDIFF(month, 0, getdate()) - 12, 0) -- How far back to look (-12 = 12 Months)Hi Aram, I don't believe we have such function readily available in Snowflake, so you can consider writing your own UDF to do this. 123 seconds, not 1. event_id, evnt. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号(-)を使用して日付を減算することもできます。 TIMESTAMPDIFF. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. 1. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go. functions. 複数の行が評価される場合(例: 入力が複数の行を含むテーブルの列名である場合)、値が秒. Then you try to use this number with the DATEADD function, and it expects to have a date instead. array_aggThat looks like a good way of handling it, Simon. DATEDIFF(YY, @DOB, @NOW) - CASE WHEN DATEADD(YY, DATEDIFF(YY, @DOB, @NOW), @DOB) > @NOW THEN 1 ELSE 0 END It's actually adding difference in years to DOB and if it is bigger than current date then subtracts one year. Pramit Marattha. For timestamp_expr, the time portion of the input value. There are several ways to approach this, but here's the way I do it with SQL Generator function Datespine_Groups. A general expression. Improve this answer. Snowflake is a complete SaaS offering that requires no maintenance. g. The reason I like to do it this way, is because its. firstdate)), AVG(AVG(DATEDIFF('days',dex. functions. snowflake. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Viewed 11k times. nanosecond uses the hour, minute, second, and all nine digits of the. I've attached an example similar to what I'm trying to achieve. –string_expr or timestamp_expr or variant_expr or integer. SELECT date_from ,date_to ,part ,case part when 'month' then datediff ('month', date_from, date_to) when 'day' then datediff ('day', date_from, date_to) when 'hour' then datediff ('hour', date_from, date_to). which yields an output of: float_serial_number. functions. What is the best reusable way to calculate the total number of seconds that occurred on business days between two datetime values (ignoring weekends and federal holidays)? Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. INTERVAL data types aren’t supported in Snowflake, but date calculations can be done with the date comparison functions (e. approx_count_distinct. Possible Values. TABLES WHERE TABLE_SCHEMA = 'REPORTING' AND TABLE_NAME ='LOGS' AND MINUTES_SINCE_LAST_UPDATE >. Thanks! Expand Post. Das Minuszeichen ( -) kann auch zum Subtrahieren von Datumsangaben. But if you want to count orders over some subset you could, for example, count customers by order type:. The DATEDIFF function will still work, but you'll want to make sure the input parameters are correct. -2. To run a stored procedure inside a transaction, you. approx_percentile_estimate. we are evaluating both products, Snowflake as a data warehouse and PowerBI as the visualisation platform for dashboarding / reporting needs. 1239') は1. For example, We want to get the difference between Jan 10th 2021 and Jan 25th 2021, then the resultant. 小数秒は丸められません。. These functions are alternatives to using the DATE_PART (or EXTRACT) function with the equivalent date part (see. I am looking to understand what the average amount of days between transactions is for each of the customers in my database using Snowflake. If the datasource was previously pointing to SQL Server or DB2 and is now going to Snowflake, there might be some incorrect results when using the days_between. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. Upon running the query you can find the Date Column with date format 'YYYY-MM-DD' and I want to change it to 'DD/MM/YYYY'. checkin_date, '2018-08-01') <= 7, 1, 0)) as visits_past_7_days, sum(iff(datediff(DAY, uc. When operating on a large quantity of data, gaps can appear in a sequence. About; Products For Teams; Stack Overflow Public questions & answers; Stack Overflow for Teams Where developers & technologists share private knowledge. A window function is generally passed two parameters: A row. 2 Answers. Thanks for help . datediff. I am trying to get the same output in Snowflake, but cant figure out how to return a float. DATEDIFF. In this article, we will check what are c ommonly used date functions in the Snowflake cloud data warehouse. TIMEADD. Account_Usage. Teams. Here is an example Here is an exampleSnowflake bills for this idle time, and therefore it can be helpful to "charge back" this cost to the query. approx_percentile_estimate. Show more actions. ほとんどのユースケースでは、Snowflakeは文字列としてフォーマットされた日付とタイムスタンプの値を正しく処理します。I'm trying to convert the below MSSQL query expression into Snowflake, can any please help me get the equivalent snowflake query. Along with Preeti Shrimal, Adwate Kumar. BR. working_day_start_timestamp then w. If the variant contains a date, the date value is preserved as is. SQL Server Syntax DATEDIFF(datePart, date1, date2) The DATEDIFF() function in SQL Server has three required parameters:. It is following snowflake's documentation. content_copy. For example, if you want to subtract 7 days from a date, the syntax would be: SELECT DATEADD ( DAY, -7, CURRENT_TIMESTAMP ()) Remember that the interval parameter must be in. Solution. I need to calculate the average DateDiff where the two dates are in separate data sources. Use conditional aggregation: select id1, id2, avg (case when datediff < 14 then n_products end) as avg_lt14, avg (case when datediff >= 14 and datediff <= 28 then n_products end) as avg_14_28, avg (case when datediff > 29 then n_products end) as avg_29pl from t group by id1, id2; Some databases calculate the averages of integers as. Actually, the marked answer originally produced wrong results for milliseconds 1 - 99: Example 1 second, 27 milliseconds: DATEDIFF % 1000 will return 27. I tried with this, but this is the last 7 days, without considering week end or start. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. functions. Scaffolding your data can be the key to creating analyses such as the current number of open tickets on a given day or displaying the number. Alternative for DATEDIFF. これらの関数(および日付部分)はセッションパラメーターを無視します. If you don't mind give me your company name (as snowflake customer name), and I can add it to the list so it may help increase the priority. Notice that the DATEDIFF() function considers only the date components for calculation and disregards the time components. A window function is generally passed two parameters: A row. Image file Snowflake Datediff ignores timezones. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. In SQL Server here's a little trick to do that: SELECT CAST(FLOOR(CAST(CURRENT_TIMESTAMP AS float)) AS DATETIME) You cast the DateTime into a float, which represents the Date as the integer portion and the Time as the fraction of a day that's passed. How can get a list of all the dates between two dates (current_date and another date 365 days out). Must be one of the values listed in Supported Date and Time Parts (e. Discover the latest in AI, genAI, Apache Iceberg, streaming, privacy-preserving collaboration, flexible programmability, application. Expression to be converted into a time: For string_expr, the result of converting the string to a time. What is the desired behavior?A number of seconds (if scale = 0 or is absent) or fractions of a second (e. select count(*) from orders. Currently, my code just returns zero on the right side of the decimal place. Snowflake SQL Query - Invalid Argument Function Using DATEADD() Hot Network QuestionsThis function uses sequences to produce a unique set of increasing integers, but does not necessarily produce a gap-free sequence. The reason I like to do it this way, is because its flexible enough that I can add weekly, hourly, or monthly intervals between the dates and reuse the code. date_or_time_part 은. g. 300'); You can truncate the milliseconds and leave the same data type, you will still see zeros but not different values:First. 0. Use the Snowpark API to call system-defined functions, UDFs, and stored procedures. If you combing using BEGIN and END block then you cannot set a session variable inside the block. For example, you can use interval data type functions to add years, months, days, hours, etc to the timestamp variables. 44597. Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO_DATE、 TO_TIME または TO_TIMESTAMP を呼び出すことをお勧めします。. Alias for DATEADD. If the data type is TIME, then the date_or_time_part must be in units of hours or smaller, not days or bigger. > Snowflake Forums. I will use floating point maths to make my point. I am trying to understand window functions in Snowflake better. Created_Date)/86400 >=8. The start position is 1-based, not 0-based. I'm trying to calculate an age value for our users based on their birthday, which one would expect to be a simple enough operation. SELECT date_from ,date_to ,part ,case part when 'month' then datediff ('month', date_from, date_to) when 'day' then datediff ('day', date_from, date_to) when 'hour' then datediff ('hour', date_from, date_to). 'a string') and string arguments that are not constants to the type NUMBER (18,5). Minute of the specified hour. When date_or_time_part is dayofweek or yearofweek (or any of their variations), the output is controlled by the. Extracts the corresponding date part from a date or timestamp. Learn more about TeamsThe LAG () function is used to extend the delay or fall behind to perform an action. Is there any inbuilt function that provides the timestamp instead of computing the datediff every time? In both cases above the output timestamp is epoch timestamp corresponding to the CURRENT_DATE (which is the. SQL. DATETIME. Make sure that the data type of each column is consistent across the rows from different sources. これは、追加する時間単位を示します。例えば、2日を追加する場合、これは DAY になります。 この測定単位は、 サポートされている日付と時刻の部分 にリストされている値のいずれかでなければなりません。 valueThe syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. Snowflake separates compute from storage, allowing for flexible pricing and configuration. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. Input: DAY ----- 2022-06-09 2022-04-04 Output DAY_MONTH -----. Snowflake passing parameters. Berechnet die Differenz zwischen zwei Datums-, Zeit- oder Zeitstempelausdrücken anhand der angeforderten Datums- oder Zeitkomponente. My Snowflake SQL Query : SELECT O. , datediff (minute, p. The spark datediff is different from snowflake datediff this can imply some manual changes. functions. SELECT DATEDIFF(MINUTE, LAST_ALTERED, CURRENT_TIMESTAMP()) AS MINUTES_SINCE_LAST_UPDATE FROM MONITORING. snowpark. Setting variables in snowflake. 1 to be 0. functions. Snowflake DATEDIFF function returns the difference between 2 dates thus it doesn't accept NUMBER as an argument in place of a date. . datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. For example, Snowflake supports the following values: YEAR, QUARTER, MONTH, WEEK, DAY, HOUR,. How to get difference betwen these below two dates in snowflake. was asking for, but useful for those looking to generate a list of dates in Snowflake SQL. For the second record, it. 000. DATEDIFF on several events for specific value. So, in your code where you have, for example sum(iff(iscode=1,1,0)), you. Invalid function type [DATEDIFF] for window function. If either the input_expr or the scale_expr is NULL, the result is NULL. The expression to be returned based on the specified offset. Improve this answer. これは、追加する時間単位を示します。例えば、2日を追加する場合、これは DAY になります。 この測定単位は、 サポートされている日付と時刻の部分 にリストされている値のいずれかでなければなりません。 The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff ( < date part > , < start date / time > , < end date / time > ) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. Create the stored procedure. DATEDIFF(MONTH, 0, @date), 0) AS First_Day_of_Month SELECT @date - DAY(@date) + 1 AS FIRST_DAY_OF_DATE -- In SQL Server 2012 and above SELECT DATEADD(DAY, 1, EOMONTH(@date, -1)). snowflake. However, the functions above will count all the days between the two specified dates. Snowflake Date Functions. In terms of indexing capabilities, Databricks offers hash integrations whereas Snowflake offers none. Default is 1. Create an intermediate temporary table, e. 5 to 0), pass in 'HALF_TO_EVEN' for the rounding_mode argument. I'm having trouble getting it to run in snowflake. By default, half-points are rounded away from zero for decimals. select datediff ( day, Date ('Tue Jan 01 1980 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp, Date ('Tue Jan 01 2020 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp ); The function you mentioned will return the difference in days between the two dates specified. Supported date and. dow_string. BOO_DateCI, ___Bookings. If you are trying to use add_months rather than dateadd than the query should be .